Optimal. Leaf size=105 \[ -\frac{(a C+b B) \sin ^3(c+d x)}{3 d}+\frac{(a C+b B) \sin (c+d x)}{d}+\frac{(4 a B+3 b C) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} x (4 a B+3 b C)+\frac{b C \sin (c+d x) \cos ^3(c+d x)}{4 d} \]
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Rubi [A] time = 0.207602, antiderivative size = 105, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 36, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.194, Rules used = {3029, 2968, 3023, 2748, 2635, 8, 2633} \[ -\frac{(a C+b B) \sin ^3(c+d x)}{3 d}+\frac{(a C+b B) \sin (c+d x)}{d}+\frac{(4 a B+3 b C) \sin (c+d x) \cos (c+d x)}{8 d}+\frac{1}{8} x (4 a B+3 b C)+\frac{b C \sin (c+d x) \cos ^3(c+d x)}{4 d} \]
Antiderivative was successfully verified.
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Rule 3029
Rule 2968
Rule 3023
Rule 2748
Rule 2635
Rule 8
Rule 2633
Rubi steps
\begin{align*} \int \cos (c+d x) (a+b \cos (c+d x)) \left (B \cos (c+d x)+C \cos ^2(c+d x)\right ) \, dx &=\int \cos ^2(c+d x) (a+b \cos (c+d x)) (B+C \cos (c+d x)) \, dx\\ &=\int \cos ^2(c+d x) \left (a B+(b B+a C) \cos (c+d x)+b C \cos ^2(c+d x)\right ) \, dx\\ &=\frac{b C \cos ^3(c+d x) \sin (c+d x)}{4 d}+\frac{1}{4} \int \cos ^2(c+d x) (4 a B+3 b C+4 (b B+a C) \cos (c+d x)) \, dx\\ &=\frac{b C \cos ^3(c+d x) \sin (c+d x)}{4 d}+(b B+a C) \int \cos ^3(c+d x) \, dx+\frac{1}{4} (4 a B+3 b C) \int \cos ^2(c+d x) \, dx\\ &=\frac{(4 a B+3 b C) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{b C \cos ^3(c+d x) \sin (c+d x)}{4 d}+\frac{1}{8} (4 a B+3 b C) \int 1 \, dx-\frac{(b B+a C) \operatorname{Subst}\left (\int \left (1-x^2\right ) \, dx,x,-\sin (c+d x)\right )}{d}\\ &=\frac{1}{8} (4 a B+3 b C) x+\frac{(b B+a C) \sin (c+d x)}{d}+\frac{(4 a B+3 b C) \cos (c+d x) \sin (c+d x)}{8 d}+\frac{b C \cos ^3(c+d x) \sin (c+d x)}{4 d}-\frac{(b B+a C) \sin ^3(c+d x)}{3 d}\\ \end{align*}
Mathematica [A] time = 0.220838, size = 91, normalized size = 0.87 \[ \frac{-32 (a C+b B) \sin ^3(c+d x)+96 (a C+b B) \sin (c+d x)+24 (a B+b C) \sin (2 (c+d x))+48 a B c+48 a B d x+3 b C \sin (4 (c+d x))+36 b c C+36 b C d x}{96 d} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.016, size = 107, normalized size = 1. \begin{align*}{\frac{1}{d} \left ( Cb \left ({\frac{\sin \left ( dx+c \right ) }{4} \left ( \left ( \cos \left ( dx+c \right ) \right ) ^{3}+{\frac{3\,\cos \left ( dx+c \right ) }{2}} \right ) }+{\frac{3\,dx}{8}}+{\frac{3\,c}{8}} \right ) +{\frac{bB \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) }{3}}+{\frac{aC \left ( 2+ \left ( \cos \left ( dx+c \right ) \right ) ^{2} \right ) \sin \left ( dx+c \right ) }{3}}+Ba \left ({\frac{\cos \left ( dx+c \right ) \sin \left ( dx+c \right ) }{2}}+{\frac{dx}{2}}+{\frac{c}{2}} \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.12894, size = 136, normalized size = 1.3 \begin{align*} \frac{24 \,{\left (2 \, d x + 2 \, c + \sin \left (2 \, d x + 2 \, c\right )\right )} B a - 32 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} C a - 32 \,{\left (\sin \left (d x + c\right )^{3} - 3 \, \sin \left (d x + c\right )\right )} B b + 3 \,{\left (12 \, d x + 12 \, c + \sin \left (4 \, d x + 4 \, c\right ) + 8 \, \sin \left (2 \, d x + 2 \, c\right )\right )} C b}{96 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.69143, size = 205, normalized size = 1.95 \begin{align*} \frac{3 \,{\left (4 \, B a + 3 \, C b\right )} d x +{\left (6 \, C b \cos \left (d x + c\right )^{3} + 8 \,{\left (C a + B b\right )} \cos \left (d x + c\right )^{2} + 16 \, C a + 16 \, B b + 3 \,{\left (4 \, B a + 3 \, C b\right )} \cos \left (d x + c\right )\right )} \sin \left (d x + c\right )}{24 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 4.78366, size = 255, normalized size = 2.43 \begin{align*} \begin{cases} \frac{B a x \sin ^{2}{\left (c + d x \right )}}{2} + \frac{B a x \cos ^{2}{\left (c + d x \right )}}{2} + \frac{B a \sin{\left (c + d x \right )} \cos{\left (c + d x \right )}}{2 d} + \frac{2 B b \sin ^{3}{\left (c + d x \right )}}{3 d} + \frac{B b \sin{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{d} + \frac{2 C a \sin ^{3}{\left (c + d x \right )}}{3 d} + \frac{C a \sin{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{d} + \frac{3 C b x \sin ^{4}{\left (c + d x \right )}}{8} + \frac{3 C b x \sin ^{2}{\left (c + d x \right )} \cos ^{2}{\left (c + d x \right )}}{4} + \frac{3 C b x \cos ^{4}{\left (c + d x \right )}}{8} + \frac{3 C b \sin ^{3}{\left (c + d x \right )} \cos{\left (c + d x \right )}}{8 d} + \frac{5 C b \sin{\left (c + d x \right )} \cos ^{3}{\left (c + d x \right )}}{8 d} & \text{for}\: d \neq 0 \\x \left (a + b \cos{\left (c \right )}\right ) \left (B \cos{\left (c \right )} + C \cos ^{2}{\left (c \right )}\right ) \cos{\left (c \right )} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.57557, size = 120, normalized size = 1.14 \begin{align*} \frac{1}{8} \,{\left (4 \, B a + 3 \, C b\right )} x + \frac{C b \sin \left (4 \, d x + 4 \, c\right )}{32 \, d} + \frac{{\left (C a + B b\right )} \sin \left (3 \, d x + 3 \, c\right )}{12 \, d} + \frac{{\left (B a + C b\right )} \sin \left (2 \, d x + 2 \, c\right )}{4 \, d} + \frac{3 \,{\left (C a + B b\right )} \sin \left (d x + c\right )}{4 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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